[Yoda]

During my GSEB this October I learned a turned shoulder plane to be a planeangle with static reference-points from adress. The static reference point was set after a horizontal line from the top of the right shoulder and back. Where another line from the plane line up through the right triceps met the first line is this referens point for the turned shoulder plane. When we looked at videos of a player at the top he had the hands in line with the right shoulder (before the course I would have called this a turned shoulder plane) and reached the static reference point for square shoulder plane but with a more rotated look to the shoulders we learned it to be a square sholder plane...!?

This confuses me a bit. Is turned shoulder plane a static plane or is every planeangle where the hands are in line with the right shoulder a turned shoulder plane. When I read 10-6-b I understand the turned shoulder plane to be a "flexible" planeangle?


Thanks

Hello Anders,

At the Top, when using the Turned Shoulder Plane, the Hands, Right Shoulder and the Ball all lie in the same Plane. There can be Backstroke Shifts to this Plane (Single Shift / 10-7-B) or from this Plane (Double Shift / 10-7-C; Triple Shift / 10-7-D; and Reverse Shift / 10-7-E). To this extent, the Turned Shoulder Plane is "flexible", but there is no language in 10-6-B to that effect.