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A book named "The science of Golf" published in Feb, 2009 not only mentioned CF but also with calculation...Dr John Wesson....who are you?
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Mandarin/Orange |
I'm beggin ya Danny
That match would be better than watching Ultimate Fighting. Please I'm beggin' ya to have it. I'll skip going to Augusta for that one............maybe not.
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More Delusion
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I suggest EdZ, MikeO, and Collin Neeman. :golf: |
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Yes that guy.... Just because a book gets published does not mean the author knows what he/shes talking about. At least in his physics of soccer book... Wesson doesn't know what he's talking about (with respect to the physics of release). In figure 2.3 of that book he's got one of those (wrong) imaginary arrows I refer above. http://img21.imageshack.us/img21/7340/wesson.gif There is no force out there... CF or otherwise! The only force the lower leg (in this case) or golf club (in our case) experiences is the force applied at the at the knee or at the hands (disregarding the minor contribution due to gravity)! Try thinking about it this way.... Forces are vector quantities, they have both direction and magnitude. If you draw an infinite line in the direction of the force and if that line does not happen to go through the center of gravity of that object then when that force is applied it will cause the object to not only translate but also rotate. Grab the periphery of almost any object and pull... does it rotate? Its inertia that causes the object to not only translate but also rotate when the "line of action" of the force does not go through the CG. In essence... THIS not CF is what causes release. http://books.google.com/books?id=dGc... =0_0#PPA21,M1 Have at it I've got to catch a flight now... PS LynnB we will see... on second thought no way... pissing matches are for school yards :) |
The Great Pretenders
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The truth is, no_mind, that despite your condescending and incorrect labeling, we here at LBG have learned to make the golf ball behave. And, despite your counsel to our readers that they "humor" us and "move on", we have demonstrated our ability to help our students do the same. :salut: |
Just in from Cambridge
Just if your interested:
Where Vfict (r) is the potential responsible for the centrifugal force: fc = −ω×(ω×r) = (ω2−ω ωT)r . Vfict (r) = −1 2 rT(ω2 − ω ωT)r Now, Rs and RJ are parallel and MsRs+MJRJ = 0. [Note that if a particle is moving then addi- tional Coriolis forces act that are not mentioned in @ @rVeff (r), so we can’t determine stability from Veff . Any questions? |
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If Lynn don't first write a dissertation on fluid dynamics . . . . should he tie a knot in it and hope not to piss down his leg? |
When all is said and done, who cares about what the physics of the golf swing are?
If my club head is moving at 100+ mph, but not on plane and aligned correctly at impact, what good were all the formulas when you have to look for ball in the next county? |
Force Feed
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